Run results for: looking up the last character of a string - MeasureThat.net

Run details:

User agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/122.0.0.0 Safari/537.36

Browser: Chrome 122

Operating system: Mac OS X 10.15.7

Device Platform: Desktop

Date tested: 6 months ago

Test name	Executions per second
short endsWith	26933452.0 Ops/sec
short regexp	11955802.0 Ops/sec
short charAt	14229462.0 Ops/sec
short brackets	14256519.0 Ops/sec
short CharCodeAt	14883711.0 Ops/sec
short slice	24639356.0 Ops/sec
short substr	24456252.0 Ops/sec
short substring	13945622.0 Ops/sec
long endsWidth	26683430.0 Ops/sec
long regexp	11770068.0 Ops/sec
long charAt	13890839.0 Ops/sec
long brackets	13685679.0 Ops/sec
long charCodeAt	14480058.0 Ops/sec
long slice	24437054.0 Ops/sec
long substr	23919680.0 Ops/sec
long substring	13677162.0 Ops/sec

Script Preparation code:

var shortString = 'okay'.repeat(20); // 80 characters
var longString = shortString.repeat(1000000); // 80,000,000 characters

var re = /\n$/;

Tests:

short endsWith
shortString.endsWith('\n');
short regexp
re.test(shortString)
short charAt
shortString.charAt(shortString.length-1)==='\n'
short brackets
shortString[shortString.length-1]==='\n'
short CharCodeAt
shortString.charCodeAt(shortString.length-1)===13
short slice
shortString.slice(-1)==='\n'
short substr
shortString.substr(-1)==='\n'
short substring
shortString.substring(shortString.length-1)==='\n'
long endsWidth
longString.endsWith('\n');
long regexp
re.test(longString)
long charAt
longString.charAt(longString.length-1)==='\n'
long brackets
longString[longString.length-1]==='\n'
long charCodeAt
longString.charCodeAt(longString.length-1)===13
long slice
longString.slice(-1)==='\n'
long substr
longString.substr(-1)==='\n'
long substring
longString.substring(longString.length-1)==='\n'

;