var num = "1.899999999996"
/^\d+\.\d{3,}$/.test(num)
num.includes('.')
/\.\d{3,}/.test(num)
FAQ: FAQ
Source code: GitHub/MeasureThat.net
Report issues: MeasureThat.net/Issues
Based on: Benchmark.js
Facebook page: https://www.facebook.com/MeasureThat.Net
Python benchmarks support: Pyodide