var x = Math.random() * 100000000;
var y;
y=Math.floor(x);
y=Math.round(x)
y=(0.5 + x) << 0;
FAQ: FAQ
Source code: GitHub/MeasureThat.net
Report issues: MeasureThat.net/Issues
Based on: Benchmark.js
Facebook page: https://www.facebook.com/MeasureThat.Net
Python benchmarks support: Pyodide