Run results for: **2 vs * vs Math.Pow for equated number

Run details:

User agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/100.0.4896.127 Safari/537.36

Browser: Chrome 100

Operating system: Windows

Device Platform: Desktop

Date tested: 2 years ago

Test name	Executions per second
n**2	317.4 Ops/sec
n*n	232.4 Ops/sec
Math.pow	209.6 Ops/sec
pow	224.4 Ops/sec

Script Preparation code:

const count = 1000
arr1 = []
arr2 = []
for (let i=0; i<count; i++) {
	arr1.push(Math.round(Math.random()*255))
	arr2.push(Math.round(Math.random()*255))
}

pow = Math.pow

Tests:

n**2
for (let i=0; i<arr1.length; i++) { n = arr1[i], m = arr2[i]; (n-m)**2; }
n*n
for (let i=0; i<arr1.length; i++) { n = arr1[i], m = arr2[i]; (n-m)*(n-m); }
Math.pow
for (let i=0; i<arr1.length; i++) { n = arr1[i], m = arr2[i]; Math.pow(n-m,2); }
pow
for (let i=0; i<arr1.length; i++) { n = arr1[i], m = arr2[i]; pow(n-m,2); }

Run results for: **2 vs * vs Math.Pow for equated number

(n-m)*(n-m) vs (n-m)**2 vs Math.Pow((n-m),2) 0 ≤ n,m ≤ 255 n,m ∈ ℤ

n**2

n*n

Math.pow

pow