Run results for: looking up the last character of a string - MeasureThat.net

Run details:

User agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.15; rv:88.0) Gecko/20100101 Firefox/88.0

Browser: Firefox 88

Operating system: Mac OS X 10.15

Device Platform: Desktop

Date tested: 3 years ago

Test name	Executions per second
short endsWith	53669500.0 Ops/sec
short regexp	29880094.0 Ops/sec
short charAt	598558336.0 Ops/sec
short brackets	586225792.0 Ops/sec
short CharCodeAt	593618496.0 Ops/sec
short slice	33991800.0 Ops/sec
short substr	34452224.0 Ops/sec
short substring	32999896.0 Ops/sec
long endsWidth	57714504.0 Ops/sec
long regexp	30394388.0 Ops/sec
long charAt	654380800.0 Ops/sec
long brackets	622703616.0 Ops/sec
long charCodeAt	648815040.0 Ops/sec
long slice	35199440.0 Ops/sec
long substr	35425952.0 Ops/sec
long substring	34209812.0 Ops/sec

Script Preparation code:

var shortString = 'okay'.repeat(20); // 80 characters
var longString = shortString.repeat(1000000); // 80,000,000 characters

var re = /\n$/;

Tests:

short endsWith
shortString.endsWith('\n');
short regexp
re.test(shortString)
short charAt
shortString.charAt(shortString.length-1)==='\n'
short brackets
shortString[shortString.length-1]==='\n'
short CharCodeAt
shortString.charCodeAt(shortString.length-1)===13
short slice
shortString.slice(-1)==='\n'
short substr
shortString.substr(-1)==='\n'
short substring
shortString.substring(shortString.length-1)==='\n'
long endsWidth
longString.endsWith('\n');
long regexp
re.test(longString)
long charAt
longString.charAt(longString.length-1)==='\n'
long brackets
longString[longString.length-1]==='\n'
long charCodeAt
longString.charCodeAt(longString.length-1)===13
long slice
longString.slice(-1)==='\n'
long substr
longString.substr(-1)==='\n'
long substring
longString.substring(longString.length-1)==='\n'

;