Run results for: looking up the last character of a string - MeasureThat.net

Run details:

User agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/14.1 Safari/605.1.15

Browser: Safari 14

Operating system: Mac OS X 10.15.7

Device Platform: Desktop

Date tested: 3 years ago

Test name	Executions per second
short endsWith	9822598.0 Ops/sec
short regexp	4342257.5 Ops/sec
short charAt	5838919.0 Ops/sec
short brackets	6079588.5 Ops/sec
short CharCodeAt	6327453.5 Ops/sec
short slice	11022681.0 Ops/sec
short substr	10172826.0 Ops/sec
short substring	5786320.5 Ops/sec
long endsWidth	10345365.0 Ops/sec
long regexp	23.1 Ops/sec
long charAt	6225146.0 Ops/sec
long brackets	6347367.0 Ops/sec
long charCodeAt	6227064.0 Ops/sec
long slice	11012061.0 Ops/sec
long substr	9657854.0 Ops/sec
long substring	5703595.5 Ops/sec

Script Preparation code:

var shortString = 'okay'.repeat(20); // 80 characters
var longString = shortString.repeat(1000000); // 80,000,000 characters

var re = /\n$/;

Tests:

short endsWith
shortString.endsWith('\n');
short regexp
re.test(shortString)
short charAt
shortString.charAt(shortString.length-1)==='\n'
short brackets
shortString[shortString.length-1]==='\n'
short CharCodeAt
shortString.charCodeAt(shortString.length-1)===13
short slice
shortString.slice(-1)==='\n'
short substr
shortString.substr(-1)==='\n'
short substring
shortString.substring(shortString.length-1)==='\n'
long endsWidth
longString.endsWith('\n');
long regexp
re.test(longString)
long charAt
longString.charAt(longString.length-1)==='\n'
long brackets
longString[longString.length-1]==='\n'
long charCodeAt
longString.charCodeAt(longString.length-1)===13
long slice
longString.slice(-1)==='\n'
long substr
longString.substr(-1)==='\n'
long substring
longString.substring(longString.length-1)==='\n'

;