const x = {...(new Map([[1,'a'],[2,'b'],[3,'c']]))}
const x = Object.fromEntries([[1,'a'],[2,'b'],[3,'c']])
FAQ: FAQ
Source code: GitHub/MeasureThat.net
Report issues: MeasureThat.net/Issues
Based on: Benchmark.js
Facebook page: https://www.facebook.com/MeasureThat.Net
Python benchmarks support: Pyodide